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Formwork Lateral Pressure Calculator

Smaller of the two GB 50666 formulas, plus effective head height.

Quick answer

With the default inputs: Concrete temperature 25 ℃ · Pour rate 2 m/h · Pour height 3 etc.Maximum lateral pressure 42.9 kN/m²

Edit the inputs below to recalculate.

Inputs

℃
m/h
kN/m³

Result

Maximum lateral pressure
42.9kN/m²
Setting time t05.00h
Admixture factor β11.00
Slump factor β21.15
Formula 142.9kN/m²
Formula 272.0kN/m²
Governing formulaFormula 1 governs (pour rate)
Effective head height1.79m

Per GB 50666-2011 clause 4.3.1, take the smaller of the two formulas. Pressure is triangular up to the effective head and constant above it - which is the key point: lateral pressure does not keep growing with pour height. Pumping impact, drop height and vibration surcharges are additional. Actual formwork and shore design must follow the approved temporary works scheme.

Formula

F1 = 0.22·γc·t0·β1·β2·V^(1/2)t0 = 200/(T+15)
F2 = γc·Hhydrostatic from pour height
F = min(F1, F2)smaller value
h = F/γctriangular below h, constant above
25 ℃, 2 m/h pour rate, 3 m form height, 110-150 mm slump, no retarder: t0 = 5 h, β1 = 1.0, β2 = 1.15. F1 = 42.9 kN/m², F2 = 72 kN/m², so 42.9 governs with an effective head of 1.79 m - pressure increases only over the bottom 1.79 m.

How to work it out

  1. Compute the setting correction first: t0 = 200 / (T + 15), where T is the concrete temperature as placed — not the air temperature and not the temperature at the plant.
  2. Apply equation one from GB 50666: F1 = 0.28 × γc × t0 × β × V^(1/2), where β is 1.2 with a retarder and 1.0 without, and V is the pour rate in m/h.
  3. Apply equation two: F2 = γc × H, where H is the height of the lift actually being poured, not the full formwork height.
  4. Design for the smaller of F1 and F2. The code explicitly requires the lesser value, not the greater.
  5. Effective head h = F / γc, which defines the pressure distribution diagram over the height.

Where it goes wrong

Material and cost

Lateral pressure has no cost of its own, but errors cost either way: too high and the formwork is over-tied (30-50% extra through-bolts), too low and it blows out (5000-20000 CNY per incident).

On site

Basis

FAQ

Why does doubling the pour rate only raise pressure by 1.4?
Because formula 1 uses the square root of the rate. Doubling V takes √V from 1 to 1.414. Faster pouring stacks fresh concrete on layers that have not set, but those layers are also stiffening and absorbing pressure, so the effects partly cancel. Low temperature (longer t0) and high slump raise pressure far more.
What is the effective head height for?
It defines the pressure profile: triangular growth over the top h metres, then constant maximum below that. Tie bolts and walers are designed for that one maximum, so no need to densify the lower rows. Designing for full hydrostatic over the whole height (72 kN/m² at 3 m) wastes a lot of steel.
How do I pick parameters for layered mass pours?
Use the worst case. If the lower layer has set, treat each layer separately by its own height and rate. If it is still plastic, add the residual pressure from below. In practice the allowable pour rate is back-calculated from layer thickness and the shortest setting time - that decision belongs to the site technical lead.

Cite this page

Use this format in reports, method statements or coursework. The link is permanent.

Building Calculator. Formwork Lateral Pressure Calculator. 2026-10-25. https://jianzhujisuan.com/en/formwork-pressure

Results are estimating aids only and are not a design basis. Construction and final accounts must follow the drawings, the applicable standards and an approved method statement. Anything affecting structural safety, shoring or falsework must be checked by a suitably qualified engineer.