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Anchorage Length Modification Calculator

lab times correction factors, applying the no-combination rule for 0.8 and 0.7.

Quick answer

With the default inputs: Basic anchorage lab 800 · Bar diameter 20 · Diameter over 25 mm Not over 25 mm etc.Anchorage length la 800 mm

Edit the inputs below to recalculate.
ConcreteΦ dAnchorage la
Size, coating, disturbance and cover factors multiply together; none of them may be cancelled out.

Inputs

Result

Anchorage length la
800mm
Diameter factor1.00
Coating factor1.00
Disturbance factor1.00
Combined ζa1.000
Cover factor1.00
Modified la800mm
In bar diameters40.0d

Per GB 50010-2010 clause 8.3.2: ribbed bars over 25 mm take 1.10, epoxy coated 1.25 and bars easily disturbed during construction 1.10, which may be multiplied together. Cover of 3d gives 0.80 and 5d gives 0.70, and these two never combine with the others. lab itself must come from the code tables or formula for the concrete grade, steel grade and seismic level - this tool only applies corrections. la must also satisfy the minimum-reinforcement requirement, and seismic design uses laE with an additional factor.

Formula

la = ζa × labζa is the correction factor
Multipliers>25 mm 1.10 · epoxy 1.25 · disturbed 1.10
Cover reduction0.80 at 3d, 0.70 at 5d, never combined with others
SeismiclaE = ζaE × la
lab = 800 mm, Φ20 plain, undisturbed, cover 5d: multipliers are 1.0 and the cover factor 0.70 gives la = 560 mm, i.e. 28d. If it were Φ28 epoxy coated, 1.10×1.25 = 1.375 and la = 770 mm.

How to work it out

  1. Start from the basic anchorage length lab, from tables or lab = α·(fy/ft)·d.
  2. Apply modification factors ζa: 1.10 for bars over 25 mm, 1.25 for epoxy coating, 1.10 where construction disturbs the bar.
  3. Reduce where cover is generous: 0.80 at 3d cover, 0.70 at 5d.
  4. Key rule: the reduction factors (0.8, 0.7) do not combine multiplicatively with the others. Use either the reduction or the increase — never multiply 1.25 by 0.7.
  5. Keep la at or above the tabulated minimum (generally 200 mm); in seismic design laE = ζaE × la.

Where it goes wrong

Material and cost

Every 10% of anchorage length adds roughly 2-4% to steel tonnage, since anchorage lengths carry no load but cannot be avoided. Epoxy-coated bar costs 15-25% more than plain and needs coating repair wherever damaged.

On site

Basis

FAQ

Why can 0.8 and 0.7 not combine with the other factors?
The mechanisms differ and combining them would over-credit the bar. Thick cover improves confinement and anchorage, while coating and large diameter weaken bond itself. Allowing 1.25×0.7 = 0.875 would assume the thick cover offsets the coating, which it does not - the coating also degrades the confinement benefit. Hence they act alone.
Why do bars over 25 mm need longer anchorage?
Their relative bonded area falls as diameter grows, so the same embedment provides less grip; their greater stiffness also causes more compatibility stress and splitting. Hence the 1.10 factor. Large bars often use mechanical anchorage (bearing plates, couplers) instead, which is cheaper than extending the embedment.
What counts as 'easily disturbed'?
Slipform and climbing formwork, bars moved while surrounding concrete is still plastic, pile cages and underwater placements - cases where the initial bond is repeatedly broken and needs more embedment to compensate. Ordinary beam, slab and column bars do not qualify. This is a design decision, not a site call.

Cite this page

Use this format in reports, method statements or coursework. The link is permanent.

Building Calculator. Anchorage Length Modification Calculator. 2026-10-25. https://jianzhujisuan.com/en/rebar-anchor-modify

Results are estimating aids only and are not a design basis. Construction and final accounts must follow the drawings, the applicable standards and an approved method statement. Anything affecting structural safety, shoring or falsework must be checked by a suitably qualified engineer.