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Conduit and Wiring Calculator

Conduit, wire and copper weight per circuit, all at once.

Quick answer

With the default inputs: Circuits 10 circuits · Average run per circuit 25 · Wires per conduit 3 pcs etc.Total wire length 825 m

Edit the inputs below to recalculate.

Inputs

circuits
Route length from the panel to the farthest point, not straight-line
pcs
Single phase L+N+PE is 3, three phase is 5
%
%
Panel and luminaire tails, usually 8-15%

Result

Total wire length
825m
Conduit net length250.0m
Conduit with waste262.5m
Wire net length750m
Wire with allowance825m
Copper per metre0.0222kg/m
Total copper weight18.4kg
Coils at 100 m9coils
Wire per circuit82.5m

This is a circuits × average-run estimate for early design and procurement; final quantities must be measured from drawings. Conductor size affects weight only — ampacity and voltage drop are not checked here and must be calculated separately from design current, installation method, ambient temperature and allowable drop. 1.5 mm² lighting and 2.5 mm² socket circuits are conventional but not transferable to heavy loads. Copper is taken at 8.9 g/cm³ excluding insulation, which adds about 10-15% for BV cable.

Formula

Conduit net lengthL = circuits × average run
Conduit totalL = net × (1 + conduit waste)
Wire net lengthL = conduit net × wires per conduit
Wire totalL = net × (1 + allowance)
Copper weightW = total length × area(mm²) × 8.9 ÷ 1000
10 circuits at 25 m each, 3 × 2.5 mm² per conduit: 250 m net conduit, 262.5 m with 5% waste; 750 m net wire, 825 m with 10% allowance; 18.4 kg of copper, nine 100 m coils.

How to work it out

  1. Conduit net length = circuits × average run per circuit. Measure the average along the actual route — walls, floor, around beams — never use the room diagonal.
  2. Conduit total = net × (1 + waste). Concealed work wastes 5-8% in bends, couplings and cuts; surface work 3-5%.
  3. Wire net length = conduit net × conductors per conduit. A single-phase circuit is L + N + PE, three conductors; three-phase is four or five. Omitting the earth is the standard mistake.
  4. Wire total = net × (1 + allowance). Half the box perimeter inside each distribution board, 0.3 m at each lighting point, 0.15 m at each socket — 10-15% overall.
  5. Copper weight = total length × cross-section (mm²) × 8.9 ÷ 1000 kg. 2.5 mm² is about 22 g per metre, useful for scrap valuation or checking delivered weight.
  6. Check the conduit fill: total conductor area must not exceed 40% of the conduit bore. Three 2.5 mm² conductors total 7.5 mm² against roughly 220 mm² inside PVC20 — only 3.4%, comfortable. More conductors or larger sizes need recalculating.

Where it goes wrong

Material and cost

Flame-retardant PVC20 runs 1.5-2.5 CNY/m, JDG steel 20 about 6-10, KBG about 5-8. BV2.5 cable is 180-260 CNY per 100 m coil. Chasing for concealed work is 8-15 CNY/m extra. Conduit and cable only — chasing and pulling labour excluded.

On site

Basis

FAQ

How many wires fit in one conduit?
Total conductor cross-section including insulation must stay under 40% of the conduit bore — that keeps pulling feasible and heat dissipation adequate. Practically, PVC20 has roughly a 16 mm bore and 201 mm² area, so 80 mm² is the limit; BV2.5 is about 4.2 mm overall and 13.9 mm², allowing five at most and three to four in practice. Overfilling makes pulling impossible and re-wiring later hopeless.
Why and how much wire allowance?
Terminations need slack. Each conductor in a panel is left half the panel perimeter for dressing and terminating, boxes take 100-150 mm for joints, and expansion joints need compensation. The rule is half-panel-perimeter in cabinets and 150 mm in boxes, totalling 8-15% of run length — take the upper end for short runs with many enclosures. Without allowance the wire sits under tension and loosens with heat or vibration.
Why 1.5 mm² for lighting and 2.5 mm² for sockets?
Because the loads differ. A lighting circuit is small — often 10-20 luminaires under 1 kW — and 1.5 mm² copper in conduit carries about 14-16 A, sufficient and economical. Socket circuits feed kettles, hairdryers and air conditioners, where 2.5 mm² carries 19-22 A with a C16 or C20 breaker. Kitchens, air conditioning and instant water heaters need their own 4 or 6 mm² circuits. These sizes are a safety floor, not a place to economise.

Cite this page

Use this format in reports, method statements or coursework. The link is permanent.

Building Calculator. Conduit and Wiring Calculator. 2026-10-25. https://jianzhujisuan.com/en/conduit-quantity

Results are estimating aids only and are not a design basis. Construction and final accounts must follow the drawings, the applicable standards and an approved method statement. Anything affecting structural safety, shoring or falsework must be checked by a suitably qualified engineer.