算BuildCalc

Cable Size Calculator

Design current from load, then the conductor size to carry it.

Quick answer

With the default inputs: Load 5000 W · Voltage 220 V · Power factor 0.9 etc.Phase conductor size 4.0 mm²

Edit the inputs below to recalculate.

Inputs

W
V
1.0 resistive, 0.8-0.85 motors

Result

Phase conductor size
4.0mm²
Design current25.25A
Installation factor0.80
Required capacity31.6A
Selected capacity34A
Neutral size4.0mm²
Earth size4.0mm²
Headroom7.7%
Resistance per 100 m0.438Ω
Suggested breaker32A
Breaker vs cable capacity94%

Capacities are typical copper PVC-insulated values at 30°C; aluminium is about 0.77 of these. Long runs must also be checked for voltage drop, normally capped at 5%. Note that sizing is not only about current — mechanical strength sets a 1.5 mm² floor for copper, short-circuit withstand matters, and fire circuits need flame-retardant or fire-resistant cable.

Formula

Single phaseI = P ÷ (U × cosφ)
Three phaseI = P ÷ (√3 × U × cosφ)
Required capacityI ÷ installation factor
Selectionsmallest size whose capacity ≥ requirement
Earth conductorsame up to 16 mm², 16 mm² for 25-35
Aluminiumcapacity × 0.77
5000 W at 220 V with a 0.9 power factor in conduit: 25.25 A design current, 31.6 A required, so 4 mm² (34 A) with 4 mm² neutral and earth and a 32 A breaker.

Copper cable capacity and load at 30°C in air

Size mm²Capacity ASingle-phase kWThree-phase kWTypical use
1.5194.212.5Lighting circuits
2.5265.717.1General sockets
4347.522.4Air conditioning, kitchen
6449.729.0Small dwelling supply
106113.440.1Medium dwelling supply
168218.054.0Large dwelling supply
2510823.871.1Unit supply
3513529.788.8Floor distribution

How to work it out

  1. Fix the phase count first. Sockets, lighting and small loads are single-phase 220 V: I = P ÷ (U × cosφ). Air-conditioner outdoor units, pumps and welders are three-phase: I = P ÷ (√3 × U × cosφ). The same appliance wired differently draws 1.732 times the current, so read the nameplate.
  2. Compute current before picking a size. 5 kW at 220 V with cosφ 0.9 gives 5000 ÷ (220 × 0.9) = 25.3 A. Skipping this step and jumping straight from power to 4 mm² is the common shortcut.
  3. Apply the installation factor: 1.00 in free air, 0.80 in concealed conduit, 0.85 on tray. A 4 mm² that carries 32 A in air carries only 25.6 A in conduit — right on the 25.3 A limit.
  4. Look up the smallest size whose derated capacity covers the current. At 25.3 A in conduit, 4 mm² at 25.6 A leaves no margin, so 6 mm² is the practical answer.
  5. Size the protective earth from the phase conductor: same cross-section up to 16 mm², 16 mm² for 25-35 mm², half the phase conductor above 35 mm².
  6. For aluminium multiply the tabulated capacity by 0.77 and go up one or two sizes. Copper-to-aluminium joints must use bimetallic terminals.

Where it goes wrong

Material and cost

Copper BV cable is sold in 100 m coils: 2.5 mm² around 180-260 CNY, 4 mm² around 280-400, 6 mm² around 420-600. Flame-retardant ZR-BV adds 10-15%, low-smoke halogen-free WDZ adds 30-50%. Pulling labour for concealed work is 8-12 CNY/m; chasing walls is extra at 8-15 CNY/m. Cable only — conduit and chasing excluded.

On site

Basis

FAQ

How much can 1.5, 2.5 and 4 mm² carry?
At 220 V and unity power factor roughly: 1.5 mm² about 4.2 kW, 2.5 mm² 5.7 kW, 4 mm² 7.5 kW and 6 mm² 9.7 kW. Those are clipped-direct ceilings; in conduit take 80%, and derate further for continuous full load. Domestic practice: 1.5 for lighting, 2.5 for general sockets, 4 for air conditioning and kitchen circuits, 10-16 for the incoming supply.
Why the derating in conduit?
Because heat cannot escape. A conductor sheds heat by convection from its surface, and inside a conduit the air is still while several cables warm each other, so the same size runs much hotter. Code factors for bunched cables run 0.7-0.85, falling with the number of circuits — which is why 2.5 mm² carries 26 A clipped direct but only about 20 A in conduit.
Can the earth be smaller than the phase?
Yes, within limits: the same size up to 16 mm², 16 mm² for 25-35 mm² phases, and half the phase above 35. The earth provides a low-impedance fault path so protection operates; too small and the fault current is insufficient to trip the breaker, which is lethal in a shock. Never use the earth as a neutral.

Cite this page

Use this format in reports, method statements or coursework. The link is permanent.

Building Calculator. Cable Size Calculator. 2026-10-25. https://jianzhujisuan.com/en/wire-size

Results are estimating aids only and are not a design basis. Construction and final accounts must follow the drawings, the applicable standards and an approved method statement. Anything affecting structural safety, shoring or falsework must be checked by a suitably qualified engineer.